如何将 XmlNode 转换为 XElement？

Question

I have an old XmlNode -based code. but the simplest way to solve my current task is to use XElement and LINQ-to-XML. The only problem is that there is no direct or obvious method for converting a XmlNode to a XElement in .NET Framework.

So for starters, I want to implement a method that receives a XmlNode instance and converts it to a XElement instance.

How can I implement this conversion?

Answer 1

var xElem = XElement.Load( xmlElement.CreateNavigator().ReadSubtree() );

There are two problems with xmlElement.InnerXml used in other answer,

1- You will loose the root element (Of course, it can be handled easily)

XmlDocument doc = new XmlDocument();
doc.LoadXml("<root> <sub>aaa</sub> </root>");
var xElem1 = XElement.Load(doc.DocumentElement.CreateNavigator().ReadSubtree());
var xElem2 = XElement.Parse(doc.DocumentElement.InnerXml);

xElem2 will be <sub>aaa</sub> , without( root )

2- You will get exception if your xml contains text nodes

XmlDocument doc = new XmlDocument();
doc.LoadXml("<root> text <sub>aaa</sub> </root>");
var xElem1 = XElement.Load(doc.DocumentElement.CreateNavigator().ReadSubtree());
var xElem2 = XElement.Parse(doc.DocumentElement.InnerXml); //<-- XmlException

Answer 2

You can try using InnerXml property of XmlElement to get xml content of your element then parse it to XElement usingXElement.Parse :

public static XElement ToXELement(this XmlElement source)
{
    return XElement.Parse(source.InnerXml);
}

Answer 3

The only way to take over all is to use OuterXml.

XElement.Parse(xNode.OuterXml);

Another way is to change the outer root element via.

XElement.Parse("<NewRoot>" + xNode.InnerXml + "</NewRoot>");

Answer 4

just use it: XElement e = XElement .Load(node.CreateReader());

I hope that helps.

Example:

A real code example The image code above

public static XNode GetNodeByFilter(XNode node,ref SortedList filter, int position = 1) {

XNode result = null;

 if (filter.TryGetValue(position, out XMLSearchCriteria criteria)) { while (node != null) { XElement e = XElement.Load(node.CreateReader()); if (e.Name.LocalName.Equals(criteria.Node) && CheckIfAllAttributesMatch(e.Attributes(), criteria.Attributes)) { if (++position <= filter.Count) { result = GetNodeByFilter(e.FirstNode, ref filter, position); break; } else { result = node; } } node = node.NextNode; } } return result; }

Answer 5

There actually is a very straightforward way to convert an XNode to an XElement:

static XElement ToXElement( XNode node)
{
    return node as XElement; // returns null if node is not an XElement
}

If you are 100% certain the node is an XElement (or you are prepared to deal with the exception if it is not, then you can simply cast: (XElement)node .

Answer 6

据我所知，你可以这样做：

XElement xdoc = new XElement(node.Name, node.InnerXml);