如何找出使用PHP匹配的多语句mysql_query的哪一部分？

Question

I have a query in PHP. It's much more complex, but for clarity let's say the query is:

$query = "SELECT * FROM my_table WHERE (foo = 'bar') OR (foo = 'bar_bar') OR (foo = 'bar_bar_bar')";
$result = mysql_query($query);

Is there a way to find out for each row of $result if it matched either foo = 'bar' , foo = 'bar_bar' or foo = 'bar_bar_bar' ?

I know I could simply do this:

while($row = mysql_fetch_assoc($result) {
    switch($row['foo']) {
        case 'bar' :
        // we matched 'bar'
        break;
        case 'bar_bar' :
        // we matched 'bar_bar'
        break;
        case 'bar_bar_bar' :
        // we matched 'bar_bar_bar'
        break;
    }
}

But that's inefficient as you're basically querying your result, plus many queries and results would be way too complex to do it this way.

So, is there an easy and efficient way to find, for example an index of what statement of the query was matched, or is my best bet to split up the query in to separate queries?

Thanks.

Answer 1

Why do you have to check that ? You can directly write the required function based on the result . In the function you are gonna write instead of hard coding it to a name just give

$row['var_name'] .

Answer 2

you have to just select foo from my table

$query = "SELECT foo FROM my_table WHERE (foo = 'bar') OR (foo = 'bar_bar') OR (foo = 'bar_bar_bar')";
$result = mysql_query($query);

//You can simply use mysql_fetch_array() instead of mysql_fetch_assoc

while($row = mysql_fetch_array($result) {
    switch($row['foo']) {
        case 'bar' :
        // we matched 'bar'
        break;
        case 'bar_bar' :
        // we matched 'bar_bar'
        break;
        case 'bar_bar_bar' :
        // we matched 'bar_bar_bar'
        break;
    }
}