bash脚本中的awk脚本

Question

I want to use a awk-script inside of an bash-script. Somehow it doesn't work right.

This is my bash script:

 1 #!/bin/bash
 2
 3
 4 echo "In what file do you want to look?"
 5 read input
 6 input="1D-MA.mcr"
 7
 8 echo "What are you looking for?"
 9 read muster
10
11 echo "What is the new value?"
12 read newVal
13
14 echo "What is the name of the new file?"
15 read output
16 
18 awk -v muster="${muster}" value="${newVal}" replace.awk "$input" > "$output"

and this is my awk script

 1 #!/usr/bin/awk -f
 2
 3 $1 == "$!VARSET" && $2 ~ muster { split($2, tmp, "=");  $2=tmp[1] "=" value; print }
 4 $1 != "$!VARSET" || $2 !~ muster

Right now the bash script just takes the awk-script and writes it in front of the input-file.

Edit: I found an answer.

changed the bash script to:

 1 #!/bin/bash
 2
 3
 4 echo "In what file do you want to look?"
 5 read input
 6 input="1D-MA.mcr"
 7
 8 echo "What are you looking for?"
 9 read muster
10
11 echo "What is the new value?"
12 read newVal
13
14 echo "What is the name of the new file?"
15 read output
16 
18 awk -v muster="${muster}" value="${newVal}" -f replace.awk "$input" > "$output"

and removed the -f in the awk-script

 1 #!/usr/bin/awk 
 2
 3 $1 == "$!VARSET" && $2 ~ muster { split($2, tmp, "=");  $2=tmp[1] "=" value; print }
 4 $1 != "$!VARSET" || $2 !~ muster

Answer 1

To answer the original question (how to run an awk script inside a bash script), here is an example how you embed an awk script into your bash code:

#!/bin/bash

echo "This is bash speaking ..."    

awk -f /dev/stdin << EOF    
   BEGIN { print "... and this is actually awk!"; }    
EOF    

echo " ... and now it's me again, bash :-)"