创建一个scala函数来定义Gatling HTTP请求链

Question

I'm just a newbie in Scala and gatling.

When I define

Object A{
  val asset_sort = exec(http("Sort by Displays")
   .get("/data/analytics/reports/")
   .queryParamMap(asset_details_map)
   .queryParam("""sort""", """video_starts""")
   .check(status.is(200)))
  .pause(1)

 val device_sort = and so on ... variables.
}

Now I want to create a Scala function which return me different variable by passing certain params.

I tried something like this

val asset_sort = generateWebRequest("Sort by Displays", "video_starts", asset_details_map)

  def generateWebRequest(requestName:String, sort:String, queryParamMap:HashMap):ChainBuilder = {

    return exec(http(requestName)
     .get("/data/analytics/reports/")
     .queryParamMap(queryParamMap)
     .queryParam("""sort""", sort)
     .check(status.is(200)))
    .pause(1)
  }

But it throws error

i_ui\lib\AssetDetail.scala:47: class HashMap takes type parameters
12:50:36.708 [ERROR] i.g.a.ZincCompiler$ -   def generateWebRequest(requestName:String, sort:String, qu
eryParamMap:HashMap):ChainBuilder = {
12:50:36.710 [ERROR] i.g.a.ZincCompiler$ -

Answer 1

The "class HashMap takes type parameters" is very explicit. HashMap is a generic type, that takes 2 type parameters, one for the key type, one for the value type. Try HashMap[String, String].

Answer 2

No need to specify precisely HashMap, use the generic parent interface. Also, no need (perhaps) to specify the type of generateWebRequest, let the compiler infer it. And you usually don't have to use return in Scala.

val asset_sort = generateWebRequest("Sort by Displays", "video_starts", asset_details_map)

def generateWebRequest(requestName:String, sort:String, queryParamMap:Map[String,String]) = {
    exec(http(requestName)
            .get("/data/analytics/reports/")
            .queryParamMap(queryParamMap)
            .queryParam("""sort""", sort)
            .check(status.is(200)))
        .pause(1)
}