[英]TYPO3 menu based on couple of lists of ids
Is it possible to build menu in TypoScript which is based on couple of list of id's
for example: 是否可以在TypoScript中基于id's
列表对构建菜单,例如:
List one: 清单一:
20 = HMENU
20.special = list
20.special.value = 35, 56, 51, 43, 22
List two 清单二
30 = HMENU
30.special = list
30.special.value = 43, 1, 25, 98
etc.. 等等..
I need to insert in the footer section a six column menu with different links to different site. 我需要在页脚部分插入一个六列菜单,其中包含指向不同站点的不同链接。 Any ideas how to do that in one menu? 任何想法如何在一个菜单中做到这一点?
What about using directory
menu ? 使用directory
菜单呢?
id
of the folder. 用文件夹的id
创建一个常量。 Then create a menu like this one: 然后创建一个像这样的菜单:
# Links list 20 = HMENU 20 { special = directory special.value = {$constants.page.footer.links} 1 = TMENU 1 { noBlur = 1 NO { wrapItemAndSub = <li>|</li> ATagTitle.field = subtitle // title } ACT = 1 ACT { wrapItemAndSub = <li class="active">|</li> ATagTitle.field = subtitle // title } CUR = 1 CUR { wrapItemAndSub = <li class="active">|</li> ATagTitle.field = subtitle // title } } }
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.