使用XSSF的Excel工作表中空白单元格的结果地址

Question

I am reading an Excel sheet using POI's XSSF . The Excel sheet has thousands of rows of user information like user name, address, age, department etc.

I can read and write the Excel sheet successfully but i want to locate empty/null cell's address and want to print it as result in another sheet

example result what i want is:

Empty cell  : C5
Empty cell  : E7
Empty cell  : H8

Thanks and appreciate for discussions and replies.

Answer 1

You need to check for both Null and Blank cells. Null cells are ones that have never been used, Blank ones are ones that have been used or styled in some way that Excel has decided to keep them around in the file

The easiest way to control this fetching is with a MissingCellPolicy . Your code can then be something like:

Row r = getRow(); // Logic here to get the row of interest

// Iterate over all cells in the row, up to at least the 10th column
int lastColumn = Math.max(r.getLastCellNum(), 10);

for (int cn = 0; cn < lastColumn; cn++) {
      Cell c = r.getCell(cn, Row.RETURN_BLANK_AS_NULL);
      if (c == null) {
         // The spreadsheet is empty in this cell
      } else {
         // Do something useful with the cell's contents
         // eg...
         System.out.println("There is data in cell " + (new CellReference(c)).formatAsString());
      }
}

You can find more on this in the POI docs on iterating over rows and cells

Answer 2

As far as I unterstood your question right, this should do the trick:

XSSFCell cell = (XSSFCell) row.getCell( index );
if( cell == null )
{
  cell = (XSSFCell) row.createCell( index );
}
if( cell.getStringCellValue().trim().isEmpty() )
{
  String cellRef = CellReference.convertNumToColString( cell.getColumnIndex() );
  System.err.println( "Empty cell found: " + cellRef
          + Integer.toString( row.getRowNum() ) );
}