MySQL更新表列从一个数据库到另一个

Question

I am working on a script that updates from:

tendesig_zink_production | euid0_hikashop_product | product_quantity

to:

tendesig_zink_dev | euid0_hikashop_product | product_quantity

I have to do this because our inventory numbers are stored on the production instance. so before pushing a new version from our dev instance i have to update the dev's inventories from production prior to the push. I am a lot rusty with my mySQL, this is what i have so far I need to know what the proper query would be though.

<?php
$host1="localhost"; // destination
$base1="tendesig_zink_dev";
$user1="tendesig_zink";
$password1="1,&#GZAWiB5z";

$host2="localhost"; //source
$base2="tendesig_zink_production";
$user2="tendesig_zink";
$password2="1,&#GZAWiB5z";


$conection1 = @mysql_connect($host1, $user1, $password1) 
or die("Error reaching destination<br>".mysql_error()." nr eroare: ".mysql_errno());
print "Succesfuly connected 1! <br>";

$Db1 = @mysql_select_db($base1, $conection1)
or die("Error reaching destination database:<br>" . mysql_error(). "<br>" . mysql_errno());
print "Database1 reached!<br>"; 

$conection2 = @mysql_connect($host2, $user2, $password2) 
or die("Error reaching source<br>".mysql_error()." nr eroare: ".mysql_errno());
print "Succesfuly connected 2!<br>";

$Db2 = @mysql_select_db($base2, $conection2)
or die("Error reaching source database:<br>" . mysql_error(). "<br>" . mysql_errno());
print "Database2 reached!!<br>"; 



$query = 'create table destination_table select * from second_database.source_table'; 
//echo "<br>".$query."<br>"; 
$result2 = mysql_query($query2, $conection1) or die('Query failed: ' . mysql_error().'||'.mysql_errno());



mysql_close($conection1);
mysql_close($conection2);
?>

Answer 1

Your query is wrong. You want to do something like this:

CREATE TABLE destination_database.destination_table LIKE source_database.source_table

Then run this:

INSERT INTO destination_database.destination_table 
SELECT * FROM source_database.source_table

In (untested) PHP code:

$create_query = 'CREATE TABLE destination_database.destination_table LIKE source_database.source_table'; 
$result = mysql_query($create_query, $conection1) or die('Query failed: ' . mysql_error().'||'.mysql_errno());

$insert_query = 'INSERT INTO destination_database.destination_table SELECT * FROM source_database.source_table'; 
$result = mysql_query($insert_query , $conection1) or die('Query failed: ' . mysql_error().'||'.mysql_errno());