PHP：我有2个静态函数A和B。如何将B绑定到A，以便只能在方法A中调用B？

Question

Ex:

<?php

class BLAH {

    public static function A () 
    {
        self::B();
        //Do something
    }

    public static function B()
    {
        //Do something
    }

}

Goal: Bind B to A to make sure that B cannot be called elsewhere outside of the static method A.

Answer 1

I am guessing you want to make B either private or protected , and what you are going for is to make sure B can only be called from inside your class. BUT, if you really want to make sure B can only be called from A :

public static function B()
{
     $trace=debug_backtrace();
     $caller=array_shift($trace);
     if ($caller['function'] != 'A' || $caller['class'] != 'BLAH') {
          throw new Exception('Illegal function invocation');
     }
     else {
         //do something
     }
}

Answer 2

Simple: Protected method:

class BLAH {

    public static function A () 
    {
        self::B();
        //Do something
    }

    protected static function B()
    {
        //Do something
    }

}