在Swift中获取UITapGestureRecognizer的发件人

Question

So I'm working on a selector that reminds users to pan the object instead of tapping it. The following code is the animation:

func labelTapped(sender:UITapGestureRecognizer)->Void{
    UIView.animateWithDuration(0.2, delay: 0, options: UIViewAnimationOptions.CurveEaseIn, animations: {
        sender.view.frame = CGRectMake(sender.view.frame.origin.x + 15, sender.view.frame.origin.y, sender.view.frame.width, sender.view.frame.height)
        }, completion:
        {(value:Bool) in
            UIView.animateWithDuration(0.2, delay: 0, options: UIViewAnimationOptions.CurveEaseOut, animations: {
                sender.view.frame = CGRectMake(sender.view.frame.origin.x - 15, sender.view.frame.origin.y, sender.view.frame.width, sender.view.frame.height)
                }, completion:
                {(value:Bool) in
                })
        })
}

now back to the object itself. I'm allocating a UITapGestureRecognizer and adding it to the object, but i'm not so sure how it works, since back in Objective-C, we used to do:

UITapGestureRecognizer *tap = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(labelTapped)];

where no parameter is needed. However in Swift, I'll have to put in a parameter in the parenthesis after labelTapped , as it will give me a Missing argument for parameter #1 in call error:

let labelTap1=UITapGestureRecognizer(target: self, action: labelTapped())

How should I go about resolving this issue? thanks!

Answer 1

动作选择器是一个以冒号结尾的字符串，它告诉它有一个参数（发送者）：

let labelTap1=UITapGestureRecognizer(target: self, action: "labelTapped:")

Answer 2

  override func viewDidAppear(animated: Bool) {
        super.viewDidAppear(animated)

        let tapRecognizer = UITapGestureRecognizer(target: self, action: "handleSingleTap:")
        tapRecognizer.numberOfTapsRequired = 1
        self.view.addGestureRecognizer(tapRecognizer)

    }

 func handleSingleTap(recognizer: UITapGestureRecognizer) {

        self.view.endEditing(true)

    }