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使用std :: atomic时发生错误C2248 <bool> ::原子

[英]error C2248 while using std::atomic<bool>::atomic

Firstly, pardon me for the long post. 首先,请原谅我。

I am using boost::lockfree::spsc_queue to run on two separate threads to process FIX messages. 我正在使用boost :: lockfree :: spsc_queue在两个单独的线程上运行以处理FIX消息。 I am using quickfix for converting FIX strings from a file to convert to FIX Messages. 我正在使用quickfix从文件转换FIX字符串以转换为FIX消息。 I want to be able to pass the queue as a pointer to both threads and a boolean value that indicates whether there are still messages to be processes. 我希望能够将队列作为两个线程的指针和一个布尔值传递,该值指示是否仍有消息要进行处理。

I am getting the following error: 我收到以下错误:

Please refer the code below. 请参考下面的代码。

It is based of an example in boost documentation. 它基于boost文档中的示例。 (Waitfree Single-Producer/Single-Consumer Queue) (Waitfree单生产者/单消费者队列)

http://www.boost.org/doc/libs/1_55_0/doc/html/lockfree/examples.html http://www.boost.org/doc/libs/1_55_0/doc/html/lockfree/examples.html

I have been trying different ways to transfer the value of running and pqFixMessages to the two threads but nothing seams to work as of now. 我一直在尝试不同的方法来将running和pqFixMessages的值传递给两个线程,但是到目前为止没有任何缝隙可以工作。 I will appreciate any suggestions. 我将不胜感激任何建议。

'std::atomic<bool>::atomic' : cannot access private member declared in class 'std::atomic<bool>

Description: 描述:

Producer thread reads a file, creates FIX messages and pushes them in the queue. 生产者线程读取文件,创建FIX消息并将其推送到队列中。

Consumer thread reads the queue and processes these messages. 使用者线程读取队列并处理这些消息。 As of now, I am just displaying the session id's for debugging. 到目前为止,我仅显示会话ID以进行调试。

Main has a pointer to the queue that is passed on to both the threads. Main具有指向传递给两个线程的队列的指针。

Further Context: After this works, I want producer and consumer to be separate classes. 进一步的上下文:在完成此工作之后,我希望生产者和消费者是分开的类。

#include <iostream>
#include <thread>
#include <atomic>
#include <fstream>
#include <quickfix\Message.h>
#include <boost\lockfree\spsc_queue.hpp>


using namespace std;
using namespace boost::lockfree;

void producer(spsc_queue<FIX::Message, capacity<1024>> * pqFixMessages, std::atomic<bool> running) {
    std::string line;
    std::ifstream fixMessageStream(<filename>);
    FIX::Message currentMessage;
    while (fixMessageStream) {
        std::getline(fixMessageStream, line);
        try {
            // Erases the timestamp on messages
            currentMessage = FIX::Message(line.erase(0, 25));
            pqFixMessages->push(currentMessage);
        } catch (std::exception& ex) {
        }
    }
    running = false;
}

std::atomic<bool> done(false); 

void consumer(spsc_queue<FIX::Message, capacity<1024>> * pqFixMessages, std::atomic<bool> running) {
    FIX::Message frontOfTheQueueMessage;
    while(!pqFixMessages->empty() || running) {
        if (!pqFixMessages->empty()) {
            pqFixMessages->pop(frontOfTheQueueMessage);
            cout << frontOfTheQueueMessage.getSessionID() << endl;
        }
    }
}

int main(int argc, char * argv[]) {

    spsc_queue<FIX::Message, capacity<1024>> * pqFixMessages = 
        new spsc_queue<FIX::Message, capacity<1024>>();

    std::atomic<bool> running(true);

    thread producerThread(producer, pqFixMessages, ref(running));
    cout << "Entered Producer Thread" << endl;
    thread consumerThread(consumer, pqFixMessages, ref(running));
    cout << "Entered Consumer Thread" << endl;

    producerThread.join();
    cout << "Joined Producer Thread" << endl;
    done = true;
    consumerThread.join();
    cout << "Joined Consumer Thread" << endl;

    delete pqFixMessages;

    std::cin.get();

    return 0;

} }

std::atomic s are not copyable. std::atomic不可复制。

Hence, passing them by value to a function is not possible. 因此,无法将它们按值传递给函数。

This is for a reason. 这是有原因的。 Usually, attempting to pass them by value indicates a programming error. 通常,尝试按值传递它们表示编程错误。 They are typically used as synchronization primitives and you cannot synchronize anything with a copy. 它们通常用作同步原语,并且您无法将任何内容与副本同步。

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