[英]How to scroll the second row of listview to top of the screen
Hello I am working on demo application where I am using listview
and custom adapter. 您好,我正在开发演示应用程序,其中正在使用
listview
和自定义适配器。 I want to do that when I scroll the list when you come at position to 2 or 3 then that row should be on top of the screen means previous row should be hide completely. 当我滚动列表到位置2或3时,我想这样做,那么该行应位于屏幕顶部,这意味着上一行应完全隐藏。
Example I am on first row first time and started to scroll listview then comes to second when getview
call with position 2
then list should only show of row 2 on the screen. 示例我第一次在第一行上,开始滚动listview,然后在位置
2
getview
调用时进入第二行,然后list应该只在屏幕上显示第二行。 How I can achieve this ? 我该如何实现? Please assist.
请协助。
See screenshot when I scroll then both rows appear when I even move to row 2 then first row also appears until I move up list manually. 滚动时查看屏幕截图,然后甚至在移至第2行时都显示两行,然后还会出现第一行,直到我手动向上移动列表为止。
@Override
public View getView(int position, View convertView, ViewGroup parent) {
if(convertView == null) {
LayoutInflater mInflator = (LayoutInflater) mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = mInflator.inflate(R.layout.home_list_item, parent, false);
}
TextView mChapterContent = (TextView) convertView.findViewById(R.id.contentTextView);
// get the data from verse instance
Verse verse = rowItem.get(position);
// setting the content
mChapterContent.setText(Html.fromHtml("<html><body style=\"text-align:justify\">" + verse.getText() + "</body></html>"));
return convertView;
}
Thanks in advance. 提前致谢。
Judging from the state, it looks to me as a good use-case of Vertical View pager. 从状态来看,在我看来,它是Vertical View寻呼机的一个很好的用例。
Checkout these likes: 签出这些赞:
https://github.com/JakeWharton/Android-DirectionalViewPager/ https://github.com/JakeWharton/Android-DirectionalViewPager/
You can use the ListView
's setSelection
feature to scroll to a particular item in the list as follows... 您可以使用
ListView
的setSelection
功能滚动到列表中的特定项,如下所示...
listView.setSelection(2)
Or if you want it animated... 或者,如果您希望它具有动画效果...
listView.smoothScrollToPosition(2)
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