BW VB6和C＃CryptAcquireContext的行为差异说明请求

Question

I am at odds with the behavior of following code, mostly because I am not well versed with VB6. My VB declarations

MS_DEF_PROV_A ="Microsoft Base Cryptographic Provider v1.0"
PROV_RSA_FULL=1
CRYPT_VERIFYCONTEXT== &HF0000000

C# Declarations

const string MS_DEF_PROV = "Microsoft Base Cryptographic Provider v1.0";
uint PROV_RSA_FULL = 1;
public const uint CRYPT_VERIFYCONTEXT = 0xF0000000;

now when I run the following code

CryptAcquireContext(out hProv, null, MS_DEF_PROV, PROV_RSA_FULL, CRYPT_VERIFYCONTEXT);

And set a break point here, I see that variable in C#

CRYPT_VERIFYCONTEXT = 4026531840

While on the VB side it has value of

CRYPT_VERIFYCONTEXT = -268435456

I just wonder why is this discrepancy, shouldn't it be the same value..both values are on the same computer, just different IDEs..It might not be anything, but since I don't know much so want to understand the difference in behavior..

Thanks

Answer 1

VB6 only supports signed 32 bit numbers. To the function recieving the number the bits are the same.