使用Python进行Excel列比较

Question

I have a excel file in which there are some columns.

COL 1    | COL 2    | COL 3  

ABCD     |  ABC(D)  |   CDA  
AB CD    | ABC D    |   C D - (B)  
A B C D  | (ABCD)   |   ABCD  
ABC D    | ABDC     | ABC D  
A(BC ) D |  AD B - C|   AB CD

I want to compare every column with every other column and want to print similarities and differences between columns.

for example :

1. comparing COL 1 and COL 2

   similarities :

    None 

   differences :

    ABCD AB CD ABCD A(BC ) D ABC(D) ABC D (ABCD) ABDC AD B - C 

then comparing COL 2 and COL 3 and then comparing COL 1 and COL 3. Need only exact string match, even a whitespace considered as mismatch. It may be possible that column number may increase and comparison starts from 2nd row of the column.

How can I implement such recursive comparison in Python which gives me fast processing output?

Answer 1

You can use xlrd . First of all, read content from your file. Second, save three columns into three dictionaries, since dict works faster in comparison. Third, do comparison work and output the result.

I suggest you check API of xlrd and write code by yourself. Here is link .

Any questions, feel free to ask.

EDIT:

Here is an example.

#!/usr/bin/python
#-*- coding:utf-8 -*-

name = {1:'a', 2:'b', 3:'c'}
lname = {1:'g', 2:'b', 3:'v'}
common = {}
diff_name   = {}
diff_lname  = {}


for key in name.keys():
    if name[key] == lname[key]:
        common[key] = name[key]
    else:
        diff_name[key] = name[key]
        diff_lname[key] = lname[key]

print 'common part is:', common
print 'diff_name  is: ', diff_name
print 'diff_lname  is: ', diff_lname

Answer 2

An algorithm might be

for colA in range(0, N):
     for colB in range (colA + 1, N - 1):
        compare(colA, colB)