与__stdcall一起使用的函数指针声明与clang等效吗？

Question

I have the following declaration of a function pointer:

extern long (__stdcall *FooPtr)(int* i);

That is, a function pointer that points to a function to be called with the stdcall calling convention (in VS terms).

How can I translate this declaration so that clang understands it?

Answer 1

__attribute__((stdcall))

is the right answer: clang supports the following list of attributes which, in syntax, are very similar to gcc's ones.

eg

#if defined(__clang__) || defined(__GNUC__)
   #define stdCallConv __attribute__ ((stdcall))
#else
   ...