我可以将x轴旋转45度吗？ 试图使象形图

Question

I need to have the y axis as it but rotate my x axis by 45 degrees. cannot seem to find any help about this online. cheers in advance for any help.

code is as follows

t = nwp.get('T','1000 hPa')

lon,lat = nwp.grid()
a,b = common.gridij3(174.,-41.,lon,lat)

pressure=[1000,950,925,850,700,600,500,400,300,250,150,100]

tt=[]
td=[]
tw=[]
for level in pressure:
    tt.append(nwp.get('T','%i hPa' %level)[a,b]) # % means add hPa to value taken from level list
    td.append(nwp.get('TD','%i hPa' %level)[a,b])
    tw.append(nwp.get('TW','%i hPa' %level)[a,b])

print '---Temperatures---'
for t in tt:
    print t
print '---Dew points---'
for t in td:
    print t
print '---Wet bulb temperatures---'
for t in tw:
    print t


#invert pressure axis
plt.gca().invert_yaxis()
#need to know how to rotate x axis by 45

plt.xlabel('Temperature K')
plt.ylabel('Pressure hPa')

plt.yscale('log')

plt.plot(tt,pressure,'r',label='Temp')
plt.plot(td,pressure,label='Dew Point')
plt.plot(tw,pressure,'g',label='Wet Bulb Temperature')
plt.legend()

plt.show()

Answer 1

You didn't say which direction, do you have the degrees for your variable?

I envision something like a basic if/else:

If your new axis goes past 360, take 360 - your axis then rotate - difference and add that to 0.

// pseudocode

if x-axis + rotate < 360 x-axis = x-axis + 45 else x-axis = 0 + (45 - (360 - x-axis))

Answer 2

I found half a dozen useful pages by Googling "matplotlib skew-T";

the general approach, exemplified by Plotting straight line on semilog plot with matplotlib seems to be to calculate an appropriate x-offset for each data point, rather than rotating the axis.

You might also find https://github.com/tchubb/SkewT useful.