[英]Java Unmarshal list of objects with a class wrapper with JAXB
From an XQuery performed by BaseX server I get a result like that: 从BaseX服务器执行的XQuery我得到一个结果:
<ProtocolloList>
<protocollo>
<numero>1</numero>
<data>2014-06-23</data>
<oggetto/>
<destinatario/>
<operatore/>
</protocollo>
...
</ProtocolloList>
And I need to convert this result in a List of Protocollo objects with JAXB so that I can show them with JList. 我需要使用JAXB将此结果转换为Protocollo对象列表,以便我可以使用JList显示它们。 Thus, following one of the discussions here I've declared the following classes:
因此,在这里的一个讨论后,我宣布了以下类:
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name = "protocollo")
public class Protocollo {
private int numero;
private String data;
private String oggetto;
private String destinatario;
private String operatore;
public Protocollo(String d, String o, String des, String op) {
this.data = d;
this.oggetto = o;
this.destinatario = des;
this.operatore = op;
}
public Protocollo() {
}
@XmlElement
public int getNumero() {
return numero;
}
public void setNumero(int numero) {
this.numero = numero;
}
@XmlElement
public String getData() {
return data;
}
public void setData(String data) {
this.data = data;
}
@XmlElement
public String getOggetto() {
return oggetto;
}
public void setOggetto(String oggetto) {
this.oggetto = oggetto;
}
@XmlElement
public String getDestinatario() {
return destinatario;
}
public void setDestinatario(String destinatario) {
this.destinatario = destinatario;
}
@XmlElement
public String getOperatore() {
return operatore;
}
public void setOperatore(String operatore) {
this.operatore = operatore;
}
}
and 和
import java.util.ArrayList;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlElementWrapper;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement(name = "ProtocolloList")
public class ProtocolloList {
@XmlElementWrapper(name = "ProtocolloList")
@XmlElement(name = "protocollo")
private ArrayList<Protocollo> ProtocolloList;
public ArrayList<Protocollo> getProtocolloList() {
return ProtocolloList;
}
public void setProtocolloList(ArrayList<Protocollo> protocolloList) {
ProtocolloList = protocolloList;
}
}
and finally I execute the converion like that: 最后我执行了这样的转换:
JAXBContext jaxbContext = JAXBContext.newInstance(Protocollo.class);
Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
StringReader reader = new StringReader(this.resultXML);
protocolli = (ProtocolloList) unmarshaller.unmarshal(reader);
And I keep on getting this exception: 我继续得到这个例外:
unexpected element (uri:"", local:"ProtocolloList"). Expected elements are <{}protocollo>
I suppose I'm making some mistakes with annotations. 我想我用注释犯了一些错误。 Can you help?
你能帮我吗?
For your use case you do not need the @XmlElementWrapper
annotation. 对于您的用例,您不需要
@XmlElementWrapper
注释。 This is because the ProtocolList
element corresponds to your @XmlRootElement
annotation. 这是因为
ProtocolList
元素对应于@XmlRootElement
注释。 Then you need the @XmlElement
annotation on the property to grab each of the list items. 然后,您需要在属性上使用
@XmlElement
注释来获取每个列表项。
@XmlRootElement(name = "ProtocolloList")
public class ProtocolloList {
private ArrayList<Protocollo> ProtocolloList;
@XmlElement(name = "protocollo")
public ArrayList<Protocollo> getProtocolloList() {
return ProtocolloList;
}
}
Note: 注意:
By default you should annotate the property. 默认情况下,您应该注释该属性。 If you want to annotate the fields you should put
@XmlAccessorType(XmlAccessType.FIELD)
on your class. 如果要注释字段,则应在类上放置
@XmlAccessorType(XmlAccessType.FIELD)
。
You need to make sure your JAXBContext
is aware of the root class. 您需要确保您的
JAXBContext
知道根类。 You can change your JAXBContext
creation code to be the following: 您可以将
JAXBContext
创建代码更改为以下内容:
JAXBContext jaxbContext = JAXBContext.newInstance(ProtocolloList.class);
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