使用非root记录器获取所有级别的事件

Question

I have a non-root logger with some handlers attached, and I want the logger to pass every event to them, including events on user-defined levels - thus I did a log.setLevel(NOTSET) , which is the lowest level ( 0 ) .

That, however, makes the logger inherit the level of the parent (root) logger , which I don't want, since delivering those events to my handlers should be unconditional.

I'm wondering if log.setLevel(1) would be the right choice here. It doesn't seem elegant, so maybe there's another way of accomplishing this?

Here's a minimal example - it prints nothing, which is not what I want:

from logging import getLogger, StreamHandler, NOTSET
from sys import stdout

log= getLogger("mylogger")
handler= StreamHandler(stdout)
log.addHandler(handler)
log.setLevel(NOTSET)

log.debug("something")

Answer 1

I think you're doing it the correct way: If you were only worried about handling built-in levels, you would use log.setLevel(logging.DEBUG) without a second thought. In this case you want to cover every possible user-defined level, which can be achieved using a level of 1. I don't think this is inelegant, the only difference between this and log.setLevel(logging.DEBUG) is there's no built-in constant for the level you're using. If it makes you feel better, you could define a constant that maps to 1 to clarify what you're doing:

from logging import getLogger, StreamHandler
from sys import stdout

ALL_LEVELS = 1

log= getLogger("mylogger")
handler= StreamHandler(stdout)
log.addHandler(handler)
log.setLevel(ALL_LEVELS)

log.debug("something")