[英]Unable to remove disable property from radio buttons on click of another radio button
I have a table in which all the radio buttons are disabled except the first radio button in every row. 我有一个表格,其中所有单选按钮都被禁用,除了每行的第一个单选按钮。 I want if someone clicks on first radio button then all the radio buttons next to that becomes selectable.
我想如果有人单击第一个单选按钮,那么旁边的所有单选按钮将变为可选择状态。 below is my code but its not responding well.
下面是我的代码,但响应不佳。
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function () {
$('tr td').not(':nth-child(2)').find('input[type=radio]').prop('disabled',true);
$('tr td'):find('input[type=radio]').change(function(){
$(this).parent().nextAll().find('input[type=radio]').removeAttr('disabled');
});
});
</script>
</head>
<body>
<input type='radio' id='Q6x1_8'>Click<p>
<table border='1'>
<tr>
<td>Test1</td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
</tr>
<tr>
<td>Test2</td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
</tr>
<tr>
<td>Test3</td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
</tr>
<tr>
<td>Test4</td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
</tr>
<tr>
<td>Test5</td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
</tr>
<tr>
<td>Test6</td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
<td><input type="radio"></td>
</tr>
</table>
</body>
</html>
You have type error in :find() jquery second line 您在:find()jquery第二行中输入类型错误
//not :find()
$('tr td'):find('input[type=radio]').change(function(){
$(this).parent().nextAll().find('input[type=radio]').removeAttr('disabled');
});
// .find()
$('tr td').find('input[type=radio]').change(function(){
$(this).parent().nextAll().find('input[type=radio]').removeAttr('disabled');
});
I can Find Error at your Code 我可以在您的代码中找到错误
If It is Not Typo then 如果不是错别字
`$('tr td'):find('input[type=radio]')`
Replace 更换
$('tr td').find('input[type=radio]')
Working Fiddle http://jsfiddle.net/5ZAJk/ 工作小提琴http://jsfiddle.net/5ZAJk/
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