SQL按日期分组但保留记录

Question

I assume the php/cakephp/sql parliance. I have a History table which contains the column created of type DATETIME. I would show all the records of the History but arranged by day.

------------------------------------------
id   created                what
------------------------------------------
1    2014-01-01 08:00:00   Someone ran
2    2014-01-01 09:00:00   Someone cried
2    2014-01-02 10:00:00   Someone spoke
2    2014-01-02 18:00:00   Someone worked

And the result I am looking for

array(
'2014-01-01' => array(
                      0=>array('time'=>'8:00','what'=>'Someone ran'
                      1=>array('time'=>'9:00','what'=>'Someone cried'
                     ),
'2014-01-02' => array(
                      0=>array('time'=>'10:00','what'=>'Someone spoke',
                      1=>array('time'=>'18:00','what'=>'Someone worked',
                     )
)

I am totaly stucked. Which SQL statement should I investigate? GROUP is not good...

Answer 1

If the other reviewers agree, I would give my answer in cakephp adapted from this SO answer

 $histories = $this->History->find('all',
                    array(
                        'group'=>array('History.created')
            ));


 foreach ($histories as $item) {
                $key = date('Y-m-d',strtotime($item['History']['created']));
                if (!isset($groups[$key])) {
                    $groups[$key] = array(
                        'items' => array($item),
                        'count' => 1,
                    );
                } else {
                    $groups[$key]['items'][] = $item;
                    $groups[$key]['count'] += 1;
                }
            }