[英]PHP - Calling a function with on post submit?
Currently have this: 目前有这个:
<script>
function copyToClipboard(info, text) {
window.prompt(info, text);
}
</script>
<?php
function getLink($user) {
return '<a class="clicky" onclick="copyToClipboard(
\'Copy to clipboard: Ctrl+C, Enter\nUse this on any forum with [img] tags!\',
\'site/pcard.php?user='.$user.'\');">
<span class="label label-primary">Get Link</span>
</a>';
}
?>
<div class="well">
<form method="post">
<label>Get Signature Image</label>
<input type="text" placeholder="Username..." name="signame" />
<button type="submit" class="btn btn-primary">Look-up</button>
<?php
if (isset($_POST)) {
getLink($_POST['signame']);
}
?>
</form>
How would I go on to make this call that script with the posted info? 我将如何继续使用已发布的信息对此脚本进行调用? Also, are there any other mistakes here? 另外,这里还有其他错误吗?
Noticed 2 things: 注意两件事:
$_POST
is always there. $_POST
总是在那里。 So isset($_POST)
is always true
. 因此isset($_POST)
始终为true
。 You should check the existence of parameter within it (eg $_POST['signme']
) or check if its not empty (eg !empty($_POST)
). 您应该检查其中是否存在参数(例如$_POST['signme']
)或检查其是否不为空(例如!empty($_POST)
)。
The getLink
function doesn't really print the result out itself. getLink
函数本身并不会真正打印出结果。 It just returning the HTML string that you just ignored. 它只是返回您刚刚忽略的HTML字符串。 You should print the returns of getLink
. 您应该打印getLink
的返回。
I think this is what you needed: 我认为这是您需要的:
<script>
function copyToClipboard(info, text) {
window.prompt(info, text);
}
</script>
<?php
function getLink($user) {
return '<a class="clicky" onclick="copyToClipboard(
\'Copy to clipboard: Ctrl+C, Enter\nUse this on any forum with [img] tags!\',
\'site/pcard.php?user='.$user.'\');">
<span class="label label-primary">Get Link</span>
</a>';
}
?>
<div class="well">
<form method="post">
<label>Get Signature Image</label>
<input type="text" placeholder="Username..." name="signame" />
<button type="submit" class="btn btn-primary">Look-up</button>
<?php
if (isset($_POST['signame'])) {
print getLink($_POST['signame']);
}
?>
</form>
</div>
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