将值分配给初始化的指针

Question

When we declare a pointer, we usually initialize it to a variable (memory mapping) and then assign a value to it.

#include <stdio.h>

int i=0;

int cir_shift(int *x,int *y);

int main()
{
    int a,b,c,*temp,*d;

    d=&c;

    scanf("%d %d %d",&a,&b,&c); 
    temp=(d+3);
    *temp=c;

    cir_shift(d,temp);
    printf("%d %d %d",a,b,c);
}

int cir_shift(int *x,int *y)
{
    *x=*(x+1);
    i++;
    if(i==3)
    {
        return 0;
    }
    else
    {
        x++;
        cir_shift(x,y);
    }
}

Here, when I want to print the value of temp (*temp), it keeps crashing. I did initialize 'temp' to a memory address, but still it crashes. And, when I want to print the memory address stored at temp, it prints the value at temp (*temp). What seems to be the problem and what may the solution be? Thank you.

Answer 1

 temp=(d+3);
*temp=c;

d + 3 means 3 int after where d is pointing to. It is an invalid address as you didn't allocate anything there. So then trying to write to *temp unleashes the infinite revenge of your implementation.

You should explain what you are trying to achieve with temp=(d+3); ?