尝试修改显示/隐藏脚本，以便第一个div在页面加载时打开（Django项目）

Question

I'm working on a blog feed and have a script that currently opens up a div and displays it's (the div's) content onclick; however, I would like the first div in the feed to open when the page loads and right now I'm struggling to figure it out. I'm a serious django and javascript/jQuery noobie, so any help that can be offered with this is greatly appreciated.

Currently everything else works. The page loads the feed, all of the divs are closed and when selected they open up.

base.html

<article   id="entry-{{ object.pk }}" {% if continue_reading %} onclick="toggleArticleActive('entry-{{ object.pk }}', true);" {% endif %}>

...blog post content

</article>

tools.js

function toggleArticleActive(article_dom_id, is_active) {
  if (is_active) { // deactivate all that are active
    $('.article-active').each(function(index, value) {
      toggleArticleActive($(this).attr('id'), false);
    });
  }

  var a = $('#' + article_dom_id);
  a.attr("class", is_active ? "article-active" : "");

  if (is_active) {
    a.find(".show-when-article-active").show(); // can animate, e.g. show('slow')
    a.find(".show-when-article-not-active").hide();

    // Load questions about this entry in the main div
    $('#div_activity').load('/f/?entry=' + article_dom_id.replace('entry-','') );
  } else {
    a.find(".show-when-article-active").hide();
    a.find(".show-when-article-not-active").show();
  }
}

Answer 1

You should just be able to show the div automatically when the .ready() event is fired.

$( document ).ready(function() {
    $("#firstdiv").show();
});

Where "#firstdiv" is the id of your first div in the list. You can also select the first div using the ":first-child" selector of your containing element:

http://api.jquery.com/first-child-selector/