正则表达式python需要帮助

Question

i have a file similar to that shown below- is it possible to perform a regex expression

text1  769,230,123
text2  70
text3  213,445
text4  24,356
text5  1,2,4

to give output as shown here?

['769','230','123']
['70']
['213','445']

My current code is as follows:

with open(filename,'r') as output:
    for line in output:
        a = line
        a = a.strip()
        #regex.compile here
        print regex.findall(a)

Any help or direction would be greatly useful to me. Thank you

Answer 1

看起来您可以找到所有数字序列：

regex = re.compile("[ ,]([0-9]+)")

Answer 2

The following regex will extract the comma separated numbers from the line, and then we can apply split(',') in order to extract the numbers:

import re
line = "text1  769,230,123"
mat = re.match(r'.*? ([\d+,]+).*', line)
nums = mat.group(1).split(',')
for num in nums:
    print num

OUTPUT

769
230
123

Answer 3

The following should work for you.

>>> import re
>>> regex = re.compile(r'\b\d+\b')
>>> with open(filename, 'r') as output:
...     for line in output:
...         matches = regex.findall(line)
...         for m in matches:
...             print m

Output

769
230
123
70
213
445
24
356
1
2
4

Answer 4

You don't need regular expressions for this. Just line.split(',') .

Answer 5

Assuming you always have 2 spaces between text# and your comma separated values. Here's a simple way to extract the separated values into arrays

list = []
with open(filename,'r') as output:
    for line in output:
        line = line.strip('  ')
        list.append(line[1].strip(','))

This will produce a nested list

print list[0] #['769','230','123']
print list[1] #['70']
print list[2] #['213','445']