从自定义表单HTML上传文件

Question

I'm trying to upload a file from my custom HTML form to a PHP script. Here is the code that I have in my HTML.

<form action="test.php" method="post" enctype="multipart/form-data">
    <input id="txt" class="button" type = "text" value = "Choose File" onclick       ="javascript:document.getElementById('file').click();">
    <input id = "file" type="file" style='visibility: hidden;' name="img"    onchange="ChangeText(this, 'txt');"/>
   <input type="submit">
</form>

Here is the test.php file:

ini_set('display_errors',1);
ini_set('display_startup_errors',1);
error_reporting(-1);

$target = "i/";
if (move_uploaded_file($_FILES['img']['tmp_name'], $target)) {
     echo "The file " . basename($_FILES['img']['name']) . "has been uploaded";
} 

Here's the error on the page:

Warning: move_uploaded_file(): The second argument to copy() function cannot be a directory in /var/www/BLOCKED/test.php on line 7

Warning: move_uploaded_file(): Unable to move '/tmp/phpNxxB72' to 'i/' in /var/www/BLOCKED/test.php on line 7. Yes it's permissions of the directory are 777.

Answer 1

move_uploaded_file的第二个参数应该是文件名（带有路径）而不是目录

$target = "i/".basename($_FILES['img']['name']);

Answer 2

The error is correct. The 2nd parameter to move_uploaded_file() is not a directory, it should be a file. You just need to append the file's name to $target in the 2nd parameter. For example:

if (move_uploaded_file($_FILES['img']['tmp_name'], $target.$_FILES['img']['name'])) {
    echo "The file " . basename($_FILES['img']['name']) . "has been uploaded";
}

Answer 3

move_uploaded_file function should be like this:

move_uploaded_file($_FILES['img']['tmp_name'], $target. $_FILES["img"]["name"])

add file name at end, as $target is a directory/folder only.

Answer 4

Tantibus, as you can read here:

http://php.net/manual/en/function.move-uploaded-file.php

You must specify the file name to your target file.

Answer 5

$target = "i/".basename($_FILES['img']['name']);

您可能错过了这一点。