Oracle 查询以识别具有特殊字符的列

Question

I'm trying to write a SQL query to return rows which has anything other than alphabets , numbers , spaces and following chars '.', '{','[','}',']' Column has alphabets like Ÿ , ¿

eg:- There's a table TEST with 2 columns - EmpNo and SampleText EmpNo is simple sequence and SampleText has values like

('12345abcde','abcdefghij','1234567890','ab c d 1 3','abcd$%1234','%^*&^%$#$%','% % $ #  %','abcd 12}34{','MINNEAŸPOLIS','THAN ¿VV ¿A')

I want to write a query which should eliminate all rows which have even a single special character except .{[}] . In above example, it should return EmpNo - 1,2,3,4 and 8 I tried REGEXP_LIKE but I'm not getting exactly what I need.

Query I used:

SELECT * FROM test 
WHERE REGEXP_LIKE(sampleText, '[^A-Z^a-z^0-9^[^.^{^}]' ,'x'); 

This is not ignoring blanks and I also need to ignore closing bracket ']'

Answer 1

You can use regular expressions for this, so I think this is what you want:

select t.*
from test t
where not regexp_like(sampletext, '.*[^a-zA-Z0-9 .{}\[\]].*')

Answer 2

I figured out the answer to above problem. Below query will return rows which have even a signle occurrence of characters besides alphabets, numbers, square brackets, curly brackets,s pace and dot. Please note that position of closing bracket ']' in matching pattern is important.

Right ']' has the special meaning of ending a character set definition. It wouldn't make any sense to end the set before you specified any members, so the way to indicate a literal right ']' inside square brackets is to put it immediately after the left '[' that starts the set definition

SELECT * FROM test WHERE REGEXP_LIKE(sampletext,  '[^]^A-Z^a-z^0-9^[^.^{^}^ ]' );

Answer 3

They key is the backslash escape character will not work with the right square bracket inside of the character class square brackets (it is interpreted as a literal backslash inside the character class square brackets). Add the right square bracket with an OR at the end like this:

select EmpNo, SampleText
from test 
where NOT regexp_like(SampleText, '[ A-Za-z0-9.{}[]|]');

Answer 4

Compare the length using lengthB and length function in oracle.

SELECT * FROM test WHERE length(sampletext) <> lengthb(sampletext)