脚本结束时不要终止 python 子进程

Question

I've seen a ton of questions for the opposite of this which I find odd because I can't keep my subprocess from closing but is there a way to call subprocess.Popen and make sure that it's process stays running after the calling python script exits?

My code is as follows:

dname = os.path.dirname(os.path.abspath(__file__))
script = '{}/visualizerUI.py'.format(dname)
self.proc = subprocess.Popen(['python', script, str(width), str(height), str(pixelSize)], stdout=subprocess.PIPE)

This opens the process just fine, but when I close out of my script (either because it completes or with Ctrl+C) it also closes the visualizerUI.py subprocess, but I want it to stay open. Or at least have the option.

What am I missing?

Answer 1

删除stdout=subprocess.PIPE<\/strong>并添加shell=True<\/strong>以便它在可以分离的子shell中生成。

"

Answer 2

Another option would be to use:

import os
os.system("start python %s %s %s %s" % (script, str(width), str(height), str(pixelSize)))