我如何从gulp监视传递到其他gulp任务

Question

I'm pretty new to gulp, here's what's happening

I did have:

gulp.watch(config.build.sass + '/**/*.scss', ['sass-dev']);

But this didn't catch any new files, so after reading the docs I need to have:

gulp.watch({
    glob: config.build.sass + '/**/*.scss',
    emit: 'all'
}, ['sass-dev']);

But this throws an error: Object #<Object> has no method 'indexOf' as the last part is incorrect.

Can anyone tell me the syntax I need to run my sass-dev task on anything emitted from watch?

Answer 1

Have you tried this:

gulp.watch(config.build.sass + '/**/*.scss', {emit: 'all'}, ['sass-dev']);

?

Answer 2

Your first example seems fine. No need to use glob option. But it depends on what config.build.sass is.

gulp.watch(config.build.sass + '/**/*.scss', ['sass-dev']);

If you'd like to use glob option, try this.

gulp.watch(config.build.sass + '/**/*.scss', { some_option: value }, ['sass-dev']);