从上一页获取数据以传输到第二页PHP / MySQL

Question

so I'm querying some data from my MySQL database to fill out a drop down box dynamically, containing a Date and then a Unique ID for that date (the unique id is a primary key, and increments just in case the same date is in the database).

I'm having trouble accessing the unique ID on the second page which would query the data for the rest of my data based on the date selected. That's kinda confusing so I'll try and break it down.

Table:

===================================================

|Unique ID|User ID|Weapon|Date|Location|Range|Score|

This is for a marksmanship web page that tracks a user's score.

I have my drop down box accessing the data based on the user ID, and then it populates a dropdown box with

Date - Unique ID.

On the next page, I can get the date fine, but I'm unsure of how to get the Unique ID so I can select the rest of the data based on these two data entries.

Here's my code for this portion:

  <!--- Form. Selecting match and all the data under it. !--->
<form action = "retrieved.php"  method = "post" style="margin-bottom:0px">

<select name="date"><option value="">-- Select A Date --</option>
<?php
    // While there is a row of data, print out the date to the drop down box.
    while($row = mysqli_fetch_array($result))
      {
          echo("</option><option value=". $row['date'] . ">". $row['date'] . " 
| Unique ID: " . $row['uniqueID'] . "
                </option>");
      }
 ?>
</select>
<input type="submit" name="submit" value="Retrieve Data" />
</form>

E.G. 
DropdownBox Options:
2014-08-16 | Unique ID: 5
2014-09-17 | Unique ID: 8
2014-09-17 | Unique ID: 10
2014-09-17 | Unique ID: 25

I thought about having Two Dropdown boxes where the user selects a date and then the second dropdown has the Unique ID which would update dynamically using AJAX or jquery or something, but I'm unfamiliar with those, and would still need to know how to access the data on the next page....

My second page needs something like this:

$query = "SELECT * FROM matches WHERE id = '".$id."' AND date = '".$date."' AND uniqueID = '".$uniqueID'"; but I can't get the uniqueID variable to work. I tried using $_SESSION and $_POST but nothing is saving to the next page.

Thanks in advance!

EDIT: In the end, I want to be able to access all the data (weapon, range, score, etc) corresponding to the date and Unique ID selected.

Answer 1

You need to set the unique id in the value field of your option:

while($row = mysqli_fetch_array($result))
{
    echo(
 "</option><option value='". $row['date'] . ",".$row['uniqueId']."'>".                           </option>"
);
}

Then when retrieving the value on the next page use:

$valueArray = explode(',', $value);

This will yield an array like so:

['date', 'uniqueID']

Your query will look like this:

$query = "SELECT * FROM matches WHERE uniqueId = ".$valueArray[0] ." AND date     =".$valueArray[1]."

Note

Your query here is highly susceptible to SqlInjection

You should be using PDO or some other orm

To manage your queries and mitigate the risks of malicious sql being injected.