对与整数和字符串混合的数组进行排序 - Ruby

Question

I have an array that must be sorted with low number to high number and then alphabetical order. Must use Array#sort_by

 i_want_dogs = ["I", "want", 5, "dogs", "but", "only", "have", 3]

I want it to output:

 => [3,5,"I","but","dogs","have","only","want"]

I tried:

 i_want_dogs.sort_by {|x,y| x <=> y }

I know that is obviously wrong, but I can't figure it out with the integers and the strings combined.

Answer 1

Use the sort method with a block that defines a comparator that does what you want. I wrote a simple one that compares values when the classes are the same and class names when they are different.

def comparator(x, y)
  if x.class == y.class
    return x <=> y
  else
    return x.class.to_s <=> y.class.to_s
  end
end

Use it like this:

i_want_dogs.sort { |x, y| comparator(x, y) }

Answer 2

使用partition将数字与字符串分开，分别对每个字符进行排序并加入最终结果，例如

i_want_dogs.partition { |i| i.is_a?(Fixnum) }.map(&:sort).flatten

Answer 3

This will give you the result:

i_want_dogs.sort_by {|x| x.to_s }

UPDATE:

Thanks @vacawama who points out that it will sort numbers alphabetically. If you need to sort number by it's value, other answers will be something you need to try.

Answer 4

First you need to convert the elements in the array to a string. Try this

i_want_dogs.sort_by(&:to_s)

This will return

[3,5,"I", "but", "dogs", "have", "only" "want"]