顺序目录名称Python 3

Question

Im trying to generate directories that are numbered 1 to however many. because in python you have to convert an integer to string, which changes it to lexicographical, how do I still keep the order of the directories?

I want the directories when generated to look like this

dir1
dir2
dir3
dir4
dir5
dir6
...

Instead I get the output of

dir0
dir1
dir10
dir11
dir12
dir13
dir14
...
dir19
dir2
dir20
dir21
dir22
dir23
...

my code

totaldir = 20
while (x < totaldir):
    x += 1
    print ("start!!!")
    makestr = str("dir%s" % x)
    makedir = os.makedirs(makestr, mode=0o755, exist_ok=True)
    print (makedir)
    print ("ended!!!")

Answer 1

By output you mean you are seeing them that way in the directory from a File viewer software ( explorer in windows ).

That is because the fileviewer / explorer has been configured ( by default ) to display the contents in alphabetically sorted manner. By alphabetically sorted manner 10 comes before 2 , hence the order of dir0 then dir1 then dir10 .

If you want them to be displayed the way you expect, follow @jonrsharpe's suggestion of 0 padding the file number, so that they remain alphabetically in the same order as their numerical order.