如何跳转到iOS中的拨号盘

Question

To make a phone call, use [[UIApplication sharedApplication] openURL:@"tel://"] it's very easy.

The problem is: I don't want to dial immediately, I need when user taps the 'call' button, app jumps to dial pad in phone app, and displays specific phone number, user can press 'Call' button to make this phone call. Anybody know how can I achieve this? Appreciate!

Answer 1

iPhone SDK not allows you to dial a number from the application. But you can do it by using a UITextField . Set keyboard type to UIKeyboardTypePhonePad

textfield.keyboardType = UIKeyboardTypePhonePad;

and set that number to textfield ,

textfield.text = numberToDial;

and then call the following line when user taps on your call button

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[NSString stringWithFormat:@"tel://%@",textfield.text]]];