Python：如何在某些索引位置获取数组的值？

Question

I have a numpy array like this:

a = [0,88,26,3,48,85,65,16,97,83,91]

How can I get the values at certain index positions in ONE step? For example:

ind_pos = [1,5,7]

The result should be:

[88,85,16]

Answer 1

Just index using you ind_pos

ind_pos = [1,5,7]
print (a[ind_pos]) 
[88 85 16]


In [55]: a = [0,88,26,3,48,85,65,16,97,83,91]

In [56]: import numpy as np

In [57]: arr = np.array(a)

In [58]: ind_pos = [1,5,7]

In [59]: arr[ind_pos]
Out[59]: array([88, 85, 16])

Answer 2

The one liner "no imports" version

a = [0,88,26,3,48,85,65,16,97,83,91]
ind_pos = [1,5,7]
[ a[i] for i in ind_pos ]

Answer 3

Although you ask about numpy arrays, you can get the same behavior for regular Python lists by using operator.itemgetter .

>>> from operator import itemgetter
>>> a = [0,88,26,3,48,85,65,16,97,83,91]
>>> ind_pos = [1, 5, 7]
>>> print itemgetter(*ind_pos)(a)
(88, 85, 16)

Answer 4

You can use index arrays , simply pass your ind_pos as an index argument as below:

a = np.array([0,88,26,3,48,85,65,16,97,83,91])
ind_pos = np.array([1,5,7])

print(a[ind_pos])
# [88,85,16]

Index arrays do not necessarily have to be numpy arrays, they can be also be lists or any sequence-like object (though not tuples).

Answer 5

your code would be

a = [0,88,26,3,48,85,65,16,97,83,91]

ind_pos = [a[1],a[5],a[7]]

print(ind_pos)

you get [88, 85, 16]