[英]Type declaration [[Integer] -> Integer]
I'm learning haskell and saw function compositions. 我正在学习haskell并看到了函数组合。 Tried to composite map
and foldl
尝试复合map
和foldl
mapd = (map.foldl)
Than 比
test = (mapd (\x y -> x + y ) [1,2,3,4])
Type of test is 测试类型是
test :: [[Integer] -> Integer]
So what is this type declaration means? 那么这种类型的声明是什么意思呢?
That means that your function "test" returns a list of functions. 这意味着您的函数“test”返回一个函数列表。 And that each of those functions takes a list of integers and returns an integer. 并且每个函数都采用整数列表并返回一个整数。
test
= mapd (\x y -> x + y ) [1,2,3,4]
= mapd (+) [1,2,3,4]
= (map . foldl) (+) [1,2,3,4]
= map (foldl (+)) [1,2,3,4]
= [ foldl (+) 1
, foldl (+) 2
, foldl (+) 3
, foldl (+) 4 ]
The result is a list of functions. 结果是一系列功能。 The first function takes a list of integers, and sums it up starting from 1
. 第一个函数采用整数列表,并从1
开始对其求和。 The second is similar, but starts from 2
. 第二个是类似的,但从2
开始。 And so on for the remaining functions. 等等剩下的功能。
As fgv already stated, this is a list of functions from list of integers to integer, hence the [[Integer] -> Integer]
type. 正如fgv已经说过的,这是从整数列表到整数的函数列表,因此是[[Integer] -> Integer]
类型。
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