[英]Array strings in MIPS - an issue with a loop
I am writing a code to display an array containing a number of Strings. 我正在编写代码以显示包含多个字符串的数组。 Therefore I used a loop.
因此,我使用了一个循环。 However my counter doesn't work properly and I receive an error message and the first element (string) of an array.
但是,我的计数器无法正常工作,并且我收到错误消息和数组的第一个元素(字符串)。 Could anybody help me, please?
有人可以帮我吗?
'# $s0=count, $s1=total, $s3=data $s7=index
.data
Mssg1: .asciiz "Hello\\n" 消息1:.asciiz“您好\\ n”
Line1: .asciiz "aab\\n" 第1行:.asciiz“ aab \\ n”
Line2: .asciiz "ggdhj\\n" 第2行:.asciiz“ ggdhj \\ n”
Line3: .asciiz "uio\\n" 第3行:.asciiz“ uio \\ n”
array: .word Line1, Line2, Line3 数组:.word Line1,Line2,Line3
.globl main
.text
main: li $s1, 0 # total=0 li $s0, 3 # count=3 la $s7, array # index main:li $ s1,0#total = 0 li $ s0,3#count = 3 la $ s7,数组#索引
li $v0, 4 # print_str "Hello"
la $a0, Mssg1
syscall
l1: lw $s3, 0($s7) # data=sum[index] l1:lw $ s3,0($ s7)#data = sum [index]
add $s1, $s1, $s3 # total=total+data
addi $s7, $s7, 4 # increment
addi $s0, $s0, -1 # decrement
bne $s0, $0, l1 # if not equal 0 go back onto the loop
add $t0, $0, $s0 # t0=s0
li $v0, 4
move $a0, $t0
lw $a0, array # print_str
syscall'
$ t1的值不会在循环中更改,因此$ t7增加,您会得到不存在的数组索引:
lw $t2,0($t7) # data=array[index]
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