如何在swt jface中使用listviewer过滤列表中所需元素的列表

Question

I have created a list using SWT which displays a list of animals ex:cat,dog,camel,elephant. and now I need to search for a specific animal ex dog in search coloumn andonly that animal has to be displayed in the list. I have written the code to filter the list but the list is not getting filtered and I am not able to find where the problem is. The sample code is as follows

final List list = new List(listComposite, SWT.BORDER | SWT.MULTI | SWT.V_SCROLL);


            gridData = new GridData();
            gridData.horizontalAlignment = SWT.FILL;
            gridData.grabExcessHorizontalSpace = true;
            gridData.verticalAlignment = SWT.FILL;
            gridData.grabExcessVerticalSpace = true;
            list.setLayoutData(gridData);


            final Map<String,String> descriptionMappernewer = DescriptionParsers.getListOfFXToolMethods();
            for(String key: descriptionMappernewer.keySet())
                list.add(key);


             final MyFilter filter = new MyFilter();

            final ListViewer viewer = new ListViewer(listComposite);
            //viewer.getList();
            viewer.getList().setLayoutData(new GridData(SWT.FILL, SWT.FILL, true, true));
            //viewer.getList();
            viewer.setContentProvider(new ArrayContentProvider());
            viewer.setInput(list);
            //viewer.setComparer( list);


            /*
            comparator = new MyViewerComparator();
            viewer.setComparator(comparator);
            viewer.setSorter(sorter);
            */

            txtName.addListener(SWT.Verify, new Listener()
            {
                @Override
                public void handleEvent(Event e)
                {
                    final String oldS = ((Text) e.widget).getText();
                    final String newS = oldS.substring(0, e.start) + e.text + oldS.substring(e.end);
                    System.out.println(newS);
                    //MyFilter filter;
                    filter.setSearchText(newS);
                    viewer.refresh();
                }
            });
            viewer.addFilter(filter);

The MyFilterClass is as follows

private static class MyFilter extends ViewerFilter
    {
        private String searchString;

        public void setSearchText(String s)
        {
            this.searchString = ".*" + s + ".*";
            System.out.println(s);
        }

        @Override
        public boolean select(Viewer viewer, Object parentElement, Object element)
        {
            if (searchString == null || searchString.length() == 0)
            {
                System.out.println("no string");
                return true;
            }

            String p = (String) element;

            if (p.matches(searchString))
            {
                System.out.println(searchString);
                return true;
            }

            return false;
        }
    }    

Please help me to filter the list as I am new to jface not able to find the error

Answer 1

You are passing an org.eclipse.swt.widgets.List to the ListViewer.setInput method - this is wrong.

The code you were given in your previous question uses a java.util.List which is the correct thing to use here.

So change the list to be as shown in How to search for required elements in list using jface

So to quote from the first answer use:

List<String> input = new ArrayList<>();
input.add("Dodo");
input.add("Unicorn");
input.add("Wyvern");

viewer.setInput(input);