如何将全局变量传递给函数中的包含文件

Question

function test_something() {
    global $test;
    echo '<div>';
    include("random_file.php");
    echo '</div>
}

random_file uses $test, but even when I define $test as global I get the undefined variable $test error when I run test_something

My actual example has about 20 variables in the file I am including and the file is 500 lines long.

Answer 1

you should be fine accessing it via global $test; or $GLOBALS['test'] inside random_file.php - there is no parametrisation of includes to my knowledge

EDIT: you should even be able to use $test as-is in your include since its already locally bound and includes inherit the scope

Answer 2

您不必将变量传递到任何包含的文件，当您在主文件中声明变量时，便可以包含其他文件...您可以在任何需要的地方使用它：包含文件意味着将代码复制到主文件。

Answer 3

The answer is to define $test a global within the included file as well.

Then the undefined error goes away and $test can be used.