创建一个表，将观察结果与时间序列中以小时为单位的间隔进行分组

Question

I receive some energy data from an external system named "mid" in a MySQL table. Data is supposed to be transmitted every hour, but sometimes the system does not work and then skips an hours, eg. there is no data for 2014-8-13 10:00:00 for mid=2 in the example below. I would like to create a table that identifies all the "mid" that have missing data - in this example that would be a table with mid=2 and datehour_in=2014-8-13 10:00:00.

-- this is how my table looks like;
create table kwh_in(mid int, datehour_in datetime, kwh int);
-- these are some example values;
insert into kwh_in values(1,'2014-8-13 08:00:00', 52);
insert into kwh_in values(1,'2014-8-13 09:00:00', 51);
insert into kwh_in values(1,'2014-8-13 10:00:00', 47);
insert into kwh_in values(2,'2014-8-13 09:00:00', 28);
insert into kwh_in values(2,'2014-8-13 08:00:00', 31);
insert into kwh_in values(2,'2014-8-13 11:00:00', 32);

Answer 1

Had to rush and do this but have a look at this SQL Fiddle

Essentially, create a reference table with all the hours of a day (any date). Right join onto it and then pull rows where datehour_in has a null value. Then pull the time that the reference table has but your source doesn't.