[英]C Compiler thinks char type is int type - clang compiler
So I am going through one of those edX courses in computer science (not for credit, just to have lectures to help self-learning) and the advanced problem set has to do with decrypting passwords. 因此,我正在学习其中一门edX计算机科学课程(不是为了获得学分,而是为了帮助自学而开设讲座),而高级问题集与解密密码有关。 To get a better understanding of the function crypt() used to make the encryptions, I made the following code to figure out what was being used for the "salts" string (the man crypt() command in the terminal said: ("salt is a two-character string chosen from the set [a-zA-Z0-9./]. This string is used to perturb the algorithm in one of 4096 different ways.")) Please tell me if you can see why I am getting this error. 为了更好地理解用于进行加密的函数crypt(),我编写了以下代码来弄清楚“ salts”字符串所用的内容(终端中的man crypt()命令说:(“ salt是从[a-zA-Z0-9./]集中选择的两个字符的字符串。此字符串用于以4096种不同方式之一干扰算法。“))请告诉我是否知道我为什么得到这个错误。
Below is the code I used. 下面是我使用的代码。 I am getting this error when attempting to compile: 尝试编译时出现此错误:
test.c:37:33: error: incompatible integer to pointer conversion passing 'char' to
parameter of type 'char *'; take the address with & [-Werror,-Wint-conversion]
char *salt = strcat(whatever1,whatever2);
Code: 码:
#define _XOPEN_SOURCE //this is needed for the unistd and crypt stuff
#include <stdio.h>
#include <unistd.h> //this lets me do the crypt() fcn
#include <cs50.h> //just lets me use string as a type among w/some input fcns and is made by the course
#include <string.h>
#include <ctype.h> //this lets me use toascii()
char *word = "caesar";
char *password;
char toASCII_New(int i) //attempt to turn input to HEX then corresponding ASCII character
{
for(int num = i; num<= 172; num++)
{
for(int hex_num = 0x41; hex_num <= 0x7a; hex_num++)
{
if(num == hex_num)
{
char letter = (char) toascii(hex_num); //should convert hex to ascii here
return letter;
}
}
}
char backup = 'a';
return backup;
}
string checker(int first, int second) //Checks the inputs to see if the can be the correct SALTS input to crypt
{
for (int i = first; i<=first+25; i++)
{
for(int j = second; j<=second+25; j++)
{
char whatever1 = (char) toASCII_New(i);
char whatever2 = (char) toASCII_New(j);
char *salt = strcat(whatever1,whatever2);
password = crypt(word,salt);
int compare = strcmp(password,"50zPJlUFIYY0o"); // this is what i'm really checking
if (compare == 0)
return salt;
}
}
return "no";
}
int main(void)
{
string AA = checker(65,65);
string Aa = checker(65,97);
string aA = checker(97,65);
string aa = checker(97,97);
printf("AA: %s\nAa: %s\naA: %s\naa: %s\n",AA,Aa,aA,aa);
}
strcat is for concatenating strings not 2 separate chars. strcat用于连接字符串,而不是2个单独的字符。 "whatever1" will hold the joined string together. “ whatever1”将连接的字符串连接在一起。 Why using -dangerous- strcat operations when all you have to do is to have a 2-byte string ? 当只需要一个2字节的字符串时,为什么要使用-dangerousstrcat操作? Just use something like: 只需使用类似:
char salt[3];
salt[0]=toASCII_New(i); /* why the casting to char ? you already returned a char... */
salt[1]=toASCII_New(j);
salt[2]='\0'; /* to terminate the string properly */
Here are some general advices, as the entire code needs to be refactored: 以下是一些一般性建议,因为整个代码都需要重构:
Function toASCII_New
should be rewritten as follows: toASCII_New
函数应重写如下:
char toASCII_New(int c)
{
if (('A' <= c && c <= 'Z') || ('a' <= c && c <= 'z'))
return (char)toascii(c);
return 'a';
}
Function checker
should be rewritten as follows: 功能checker
应重写如下:
int checker(int first, int second, char salt[3])
{
for (int i=first; i<=first+25; i++)
{
for (int j=second; j<=second+25; j++)
{
salt[0] = toASCII_New(i);
salt[1] = toASCII_New(j);
password = crypt(word,salt);
if (strcmp(password,"50zPJlUFIYY0o") == 0)
return 1;
}
}
return 0;
}
Function main
should be rewritten as follows: 函数main
应该重写如下:
int main()
{
char salt_AA[3] = {0};
char salt_Aa[3] = {0};
char salt_aA[3] = {0};
char salt_aa[3] = {0};
int salt_AA_OK = checker('A','A');
int salt_Aa_OK = checker('A','a');
int salt_aA_OK = checker('a','A');
int salt_aa_OK = checker('a','a');
printf("AA: %s\n",salt_AA_OK? salt_AA:"failed");
printf("Aa: %s\n",salt_Aa_OK? salt_Aa:"failed");
printf("aA: %s\n",salt_aA_OK? salt_aA:"failed");
printf("aa: %s\n",salt_aa_OK? salt_aa:"failed");
return 0;
}
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