我们如何使用teststack.white自动化框架检查特定的模态窗口是否打开？

Question

I am having an issue relating to modal window.

Inside the application that i am automating, a modal window opens if the user has some data but if it has not then it will not open. how can we put an "if statement" eg, if modal window exist then do some work else skip. because i am having an error at this statement

Window childWindow = mainWindow.ModalWindow("child");

it is throwing an exception because it could not search for window with name "child". and i know that it does not exist. it should skip it if it does not exist.

Answer 1

You can try to se if there are any modal windows before executiong the ModalWindow Method

Window childWindow = null;
if(mainWindow.ModalWindows().Any())
{
    childWindow = mainWindow.ModalWindow("child");
}

else you can try to define criteria, or while for a certain timeout

...
var timer = new StopWatch();
timer.Start();
Window childWindow = null;
do 
{
    childWindow = mainWindow.ModalWindow("child");
} while (childWindow != null || timer.ElapsedMilliseconds < timeOutInMs);
...

Hope it helps.

Rik

Answer 2

My working code (AutomationUI):

using System.Windows.Automation;

Automation.AddAutomationEventHandler(
            WindowPattern.WindowOpenedEvent,
            mainWindow.AutomationElement,
            TreeScope.Descendants,
            (sender, e) =>
            {
                var element = sender as AutomationElement;
                if (!(element.Current.LocalizedControlType == "Dialog" && element.Current.Name == "modalWindowTitle"))
                    return;

                Automation.RemoveAllEventHandlers();
                // Here run your code. The modal window was opened
            });