bash脚本 - 从文件夹中获取最高文件名

Question

I tries a lot of whys to solve the following problem without a solution :(

I have a folder which contains files with the following name pattern:

 number_name.txt

for example:

0_test.txt
17_test.txt
39_test.txt
99_test.txt
101_test.txt
17_test.txt

I need to get the file name which contain the max prefix number.

(when I compare the strings, I'm getting that "99_test.txt" is the highest which is not true....)

Thanks

Answer 1

使用版本排序：

find -name '*.txt' | sort -V | tail -1