我如何在Mongo Shell中将其作为一个命令运行

Question

db.people.update(
    { "age": "Thirty Two" }, { age: 32 }, { upsert: false }
)

db.people.update(
    { "age": "Fifty-Five" }, { age: 55 }, { upsert: false }
)

db.people.update(
    { "age": "Twenty" }, { age: 20 }, { upsert: false }
)

I was thinking:

db.people.update(
    [{ "age": "Thirty Two" }, { age: 32 }, { upsert: false }],
    [{ "age": "Fifty-Five" }, { age: 55 }, { upsert: false }],
    [{ "age": "Twenty" }, { age: 20 }, { upsert: false }]
)

But that didn't work.. I know im just really tired and can't think of it...

Answer 1

Perhaps this is what you want.

db.eval(function(name, options) {
    var coll = db.getCollection(name);
    for (var x in options) {
        var option = options[x];
        coll.update(option[0], option[1], option[2]);
    }
},
"people",
[
    [{ "age": "Thirty Two" }, { age: 32 }, { upsert: false }],
    [{ "age": "Fifty-Five" }, { age: 55 }, { upsert: false }],
    [{ "age": "Twenty" }, { age: 20 }, { upsert: false }]
]);

Answer 2

To elaborate on my comment and present an alternative to db.eval() , a "operatorless" update replaces the entire matched document with the update document (except keeping the _id ):

> db.people.find()
{ "_id" : 0, "name" : "Barney Big", "age" : 32 }
{ "_id" : 1, "name" : "Sam Small", "age" : 26 }
{ "_id" : 2, "name" : "Mindy Medium", "age" : 26 }
> db.people.update({ "age" : 32 }, { "age" : 45 })
> db.people.find()
{ "_id" : 0, "age" : 45 }
{ "_id" : 1, "name" : "Sam Small", "age" : 26 }
{ "_id" : 2, "name" : "Mindy Medium", "age" : 26 }

Changing only one field means using an update operator like $set :

> db.people.find()
{ "_id" : 0, "name" : "Barney Big", "age" : 32 }
{ "_id" : 1, "name" : "Sam Small", "age" : 26 }
{ "_id" : 2, "name" : "Mindy Medium", "age" : 26 }
> db.people.update({ "age" : 32 }, { "$set" : { "age" : 45 } })
> db.people.find()
{ "_id" : 0, "name" : "Barney Big", "age" : 45 }
{ "_id" : 1, "name" : "Sam Small", "age" : 26 }
{ "_id" : 2, "name" : "Mindy Medium", "age" : 26 }

By default, updates affect only one matching document. The option multi=true will cause the update to affect all matching documents:

> db.people.find()
{ "_id" : 0, "name" : "Barney Big", "age" : 32 }
{ "_id" : 1, "name" : "Larry Large", "age" : 32 }
{ "_id" : 2, "name" : "Sam Small", "age" : 26 }
{ "_id" : 3, "name" : "Mindy Medium", "age" : 26 }
> db.people.update({ "age" : 32 }, { "$set" : { "age" : 45 } })
> db.people.find()
{ "_id" : 0, "name" : "Barney Big", "age" : 45 }
{ "_id" : 1, "name" : "Larry Large", "age" : 32 }
{ "_id" : 2, "name" : "Sam Small", "age" : 26 }
{ "_id" : 3, "name" : "Mindy Medium", "age" : 26 }
> db.people.update({ "age" : 26 }, { "$set" : { "age" : 23 } }, { "multi" : true })
> db.people.find()
{ "_id" : 0, "name" : "Barney Big", "age" : 45 }
{ "_id" : 1, "name" : "Larry Large", "age" : 32 }
{ "_id" : 2, "name" : "Sam Small", "age" : 23 }
{ "_id" : 3, "name" : "Mindy Medium", "age" : 23 }

So, to do the updates you asked about in your question in the shell, I'd use a for loop but dispense with the db.eval in favor of multiple calls to db.people.update()

> updates = [
    [{ "age": "Thirty Two" }, { "$set" : { "age" : 32 } }],
    [{ "age": "Fifty-Five" }, { "$set" : { "age" : 55 } }],
    [{ "age": "Twenty" }, { "$set" : { "age" : 20 } }]
]
> updates.forEach(function(pair) {
    db.people.update(pair[0], pair[1])
})

If you have hundreds of updates and are using MongoDB 2.6 or later, look into bulk operations . There's more information in the db.collection.update() docs .