用PHP解析JSON文件

Question

I had a problem when parse my json data with php in select html element

This my JSON DATA

This my PHP CODE

Error message :

Notice: Trying to get property of non-object in C:\xampp\htdocs\test\index.php on line 6

This line 6 :

$provider = $jfo->product->provider;

I try to parse "provider" to select html element after someone choose "Jenis Produk".

Answer 1

产品不是对象，而是一个数组：

$jfo->product['provider'];

Answer 2

product is an array, containing multiple products.

$jfo->product[0]->provider;

You'll need to loop through the products.

for ($i = 0; $i < sizeof($jfo->product); $i++) {
  $provider = $jfo->product[$i]->provider;
}

Answer 3

It appears that product is not an object.

Have you tried dumping $jfo->product?

My guess is that it is an array.