[英]PriorityQueue iterating only half the elements
I have program which uses PriorityQueue.我有使用 PriorityQueue 的程序。 poll() is not giving all the values in the queue.
poll() 没有给出队列中的所有值。
class Coffee {
public static void main(String[] args) {
PriorityQueue<Double> pq = new PriorityQueue<Double>();
Random rand = new Random();
for (int i = 0; i < 10; i++) {
pq.offer(rand.nextDouble());
}
System.out.println(pq);
System.out.print("size value " + pq.size());
for (int i = 0; i < pq.size(); i++) {
System.out.println(pq.poll());
}
}
}
Output:输出:
[0.005756373546009885, 0.057563473207216886, 0.3415582636412481, 0.2026760924302
6186, 0.10792479235868724, 0.768845643547834, 0.5107848139799113, 0.758559713387
8311, 0.6437353209123445, 0.5156937257761389]
size value 10
0.005756373546009885
0.057563473207216886
0.10792479235868724
0.20267609243026186
0.3415582636412481
The size is 10, so why am I not getting all the 10 values with poll()?大小是 10,那么为什么我没有通过 poll() 获得所有 10 个值?
for (int i = 0; i < pq.size(); i++) {
System.out.println(pq.poll());
}
On each loop iteration you are removing an element by pq.poll()
, which decrements pq.size()
, and you are also incrementing i
.在每次循环迭代中,您都会通过
pq.poll()
删除一个元素,这会减少pq.size()
,并且您也会增加i
。 So in the expression i < pq.size()
the two values approach each other and meet in the middle, so it only loops half the times.所以在表达式
i < pq.size()
,两个值彼此接近并在中间相遇,所以它只循环了一半。
Instead do:而是这样做:
while (!pq.isEmpty()) {
System.out.println(pq.poll());
}
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