SQL连接查询问题

Question

I've a mysql table called tutor_signup_form is look like this

id    feerange    gender    name
1     20          male      alex      
2     10          female    Robin
3     15          male      Babu

Now I've a html search form where few drop down selected fields and many Chckbox fields are exist. I want to get the search result from multiple table using sql INNER JOIN . My INNER JOIN query is look like this

// search query
$query =  mysql_query("SELECT tutor_signup_form . *, tutor_signup_edu_psle . *,
tutor_signup_edu_olevel . *, tutor_signup_edu_alevel . *, tutor_signup_edu_diploma . *,
tutor_signup_edu_degree . *, tutor_signup_edu_masters . *, tutor_signup_edu_psd . *,
tutor_signup_level_primary . *, tutor_signup_level_olevel . *, tutor_signup_level_alevel . *,
tutor_signup_level_int . *, tutor_signup_level_uni . *, tutor_signup_level_music . *,
tutor_signup_level_lang . *, tutor_signup_level_com . *, tutor_signup_pre_central . *,
tutor_signup_pre_east . *, tutor_signup_pre_west . *, tutor_signup_pre_south . *,
tutor_signup_pre_north . *, tutor_signup_pre_ne . *, tutor_signup_pre_nw . *  FROM tutor_signup_form

INNER JOIN tutor_signup_edu_psle ON tutor_signup_form.tutor_id = tutor_signup_form.tutor_id     
INNER JOIN tutor_signup_edu_olevel ON tutor_signup_form.tutor_id = tutor_signup_edu_olevel.tutor_id
INNER JOIN tutor_signup_edu_alevel ON tutor_signup_form.tutor_id = tutor_signup_edu_alevel.tutor_id 
INNER JOIN tutor_signup_edu_diploma ON tutor_signup_form.tutor_id = tutor_signup_edu_diploma.tutor_id
INNER JOIN tutor_signup_edu_degree ON tutor_signup_form.tutor_id = tutor_signup_edu_degree.tutor_id
INNER JOIN tutor_signup_edu_masters ON tutor_signup_form.tutor_id = tutor_signup_edu_masters.tutor_id
INNER JOIN tutor_signup_edu_psd ON tutor_signup_form.tutor_id = tutor_signup_edu_psd.tutor_id
INNER JOIN tutor_signup_level_primary ON tutor_signup_form.tutor_id = tutor_signup_level_primary.tutor_id
INNER JOIN tutor_signup_level_olevel ON tutor_signup_form.tutor_id = tutor_signup_level_olevel.tutor_id
INNER JOIN tutor_signup_level_alevel ON tutor_signup_form.tutor_id = tutor_signup_level_alevel.tutor_id
INNER JOIN tutor_signup_level_int ON tutor_signup_form.tutor_id = tutor_signup_level_int.tutor_id
INNER JOIN tutor_signup_level_uni ON tutor_signup_form.tutor_id =  tutor_signup_level_uni.tutor_id
INNER JOIN tutor_signup_level_music ON tutor_signup_form.tutor_id = tutor_signup_level_music.tutor_id
INNER JOIN tutor_signup_level_lang ON tutor_signup_form.tutor_id = tutor_signup_level_lang.tutor_id
INNER JOIN tutor_signup_level_com ON tutor_signup_form.tutor_id =  tutor_signup_level_com.tutor_id
INNER JOIN tutor_signup_pre_central ON tutor_signup_form.tutor_id = tutor_signup_pre_central.tutor_id
INNER JOIN tutor_signup_pre_east ON tutor_signup_form.tutor_id = tutor_signup_pre_east.tutor_id
INNER JOIN tutor_signup_pre_west ON tutor_signup_form.tutor_id = tutor_signup_pre_west.tutor_id
INNER JOIN tutor_signup_pre_south ON tutor_signup_form.tutor_id = tutor_signup_pre_south.tutor_id
INNER JOIN tutor_signup_pre_north ON tutor_signup_form.tutor_id =  tutor_signup_pre_north.tutor_id
INNER JOIN tutor_signup_pre_ne ON tutor_signup_form.tutor_id = tutor_signup_pre_ne.tutor_id
INNER JOIN tutor_signup_pre_nw ON tutor_signup_form.tutor_id = tutor_signup_pre_nw.tutor_id 

WHERE tutor_signup_form.feerange <= '$budget'");  

For example I selected budget field = 20. So my query should be product only 3 results from tutor_signup_form but it's produce 24 results. I don't understand why it's produce 24 result. Can you fix it ?

Update:

Answer 1

As Deadman mentioned, Cartesian...

Your first inner join was a copy/paste of table names

INNER JOIN tutor_signup_edu_psle 
   ON tutor_signup_form.tutor_id = tutor_signup_form.tutor_id     

should have been

INNER JOIN tutor_signup_edu_psle 
   ON tutor_signup_form.tutor_id = tutor_signup_edu_psle.tutor_id     

I have not read past that, but will in the mean-time

In addition, you have all your joins as INNER JOINs. If someone does not have a record in one of the tables (such as Music), but does tutoring in Computers, and someone searches for Computers, they will not be returned. I suggest changing to LEFT JOIN for all of them, so if the record exists in the tutoring subsidiary level, you are good and won't loose it.

Answer 2

If I've got it right you need to check your where clause.i think Cartesian product of the tables involved in the join. The size of a Cartesian product result set is the number of rows in the first table multiplied by the number of rows in the second table