关闭三星智能电视应用程序中的网页

Question

I have a samsung App that is currently streaming a video through a IP camera.

So, I made a app that opens a webpage when I click a certain button (Up arrow).

The code associated to the up arrow is :

var myWindow = window.open("http://10.0.0.164/mjpg/video.mjpg", "myWindow", "width=200, height=200");

Now the problem:

When the webpage opens, I don't have any control of the app anymore.

Isn't there a way for me , for example, press the return key to close the the opened window and go back to the app?

I tryed associating the command Window.close() to other keys, but no sucess...

Any ideias?

thank you in advance!

Pedro

Answer 1

Yes it is launching the web url launcher of the TV. I think you can try this.

Add this in HTML-

<div id="webElement" style="display:none;"></div>

On button up click, try adding the object tag to show the URL (set width and height which you want.)

var webElement = jQuery("#webElement");  
webElement.empty();  
var obj = "<object type='text/html' width='1920' height='1080' data='" + urlToShow + "' onerror='Player.onWebElementError();'> </object>";  
webElement.append(obj);  
webElement.show();  

On button back click , you can hide the div and return back to application.

var webElement = jQuery("#webElement");  
webElement.empty();  
jQuery("#webElement").hide();  

Hope it will help you a little bit.

Updated:

Add this in your project if JQuery is missing.

<script type="text/javascript" language="javascript" src="app/javascript/jquery-2.1.1.min.js"></script>

Check this URL for more info:
http://jquery.com/

Answer 2

解决方案很简单：我使用了app framework 2.0中的图像块，并将IP摄像机的URL设置为图像的src。