[英]Prolog out of local stack space/ infinite recursion
I have read other similar questions and answers on this site, but can't seem to find the answer to my particular problem. 我已经在该网站上阅读了其他类似的问题和答案,但似乎找不到我特定问题的答案。 I am trying to encode a maze in Prolog. 我正在尝试在Prolog中编码一个迷宫。 From region 0, you can move freely to regions 1 or region 3. From region 3, you can move freely to region 0, region 4, or region 5, etc. I want to find the all paths of length 7 from the beginning to the end (from 0 to 14). 从区域0,您可以自由移动到区域1或区域3。从区域3,您可以自由移动到区域0,区域4或区域5,依此类推。我想找到从头到尾长度为7的所有路径。结束(从0到14)。 I have encoded the problem in the following manner in SWI-Prolog: 我在SWI-Prolog中以以下方式编码了问题:
region(0).
region(1).
region(2).
region(3).
region(4).
region(5).
region(6).
region(7).
region(8).
region(9).
region(10).
region(11).
region(12).
region(13).
region(14).
region(15).
connection(0,1). %connection exists between these two regions
connection(0,3).
connection(1,2).
connection(1,8).
connection(1,7).
connection(3,4).
connection(3,5).
connection(7,9).
connection(7,5).
connection(7,8).
connection(5,6).
connection(8,10).
connection(8,11).
connection(11,12).
connection(11,13).
connection(13,15).
connection(13,14).
double_link(X,Y) :-
region(X),
region(Y),
( connection(X,Y) | connection(Y,X) ). %can go from region X to region Y, and vice versa
path(X,Y) :-
double_link(X,Y).
path(X,Y) :-
double_link(X,Z),
path(Z,Y).
When I execute path(14,0).
当我执行path(14,0).
I get true
. 我是true
。 However, when I execute path(0,14)., I run out of local stack space. 但是,当我执行path(0,14)。时,我用完了本地堆栈空间。 I don't know how that can be. 我不知道怎么回事。 Thanks for any help! 谢谢你的帮助!
You said: 你说:
When I execute
path(14,0).
当我执行path(14,0).
I gettrue
. 我是true
。
That is half of the truth! 那是事实的一半! Oh, even less than that! 哦,比这还少! In fact you get true
not once but many times! 其实你true
不是一次,而是很多次!
?- path(14,0).
true ;
true ;
true ;
true ;
true ;
true ...
There is a simple way to avoid typing ; 有一个简单的避免输入的方法; or SPACE all the time. 或一直保持空格 。 Simply use the goal false
. 只需将目标false
。
?- path(14,0), false **LOOPS**
And now, you can also add such false
-goals into your program. 现在,您还可以在程序中添加这些false
目标。 In this manner you are ruling out parts of the program ; 通过这种方式,您可以排除程序的某些部分; and if the remaining part still loops, you know that there must be a problem there. 如果其余部分仍然循环播放,则说明那里一定有问题。 This is what I got: 这就是我得到的:
region(0) :- false. % ...region(12) :- false. region(13). region(14).region(15) :- false.connection(0,1) :- false. % ...connection(13,15) :- false. connection(13,14). double_link(X,Y) :- region(X), region(Y), ( connection(X,Y) ; connection(Y,X) ).path(X,Y) :- false,double_link(X,Y). path(X,Y) :- double_link(X,Z), path(Z,Y), false.
So in this remaining part that loop has to be addressed. 因此,在其余部分中,必须解决该循环。 It should be now self-explanatory, isn't it? 现在应该不言自明了,不是吗?
The problem arises because you can go in circles in the maze. 出现问题是因为您可以在迷宫中盘旋。 Eg in your maze you have the connections 0 - 1 - 7 - 5 - 3 - 0
. 例如,在您的迷宫中,连接0 - 1 - 7 - 5 - 3 - 0
。 You have not taken any measures to ensure that the search does not follow those circles blindly. 您尚未采取任何措施来确保搜索不会盲目追踪这些圈子。
A usual approach would be to add an argument to your path predicate that contains the already visited regions (initially empty). 通常的方法是在您的路径谓词中添加一个参数,其中包含已经访问过的区域(最初为空)。 Then you have to ensure when you go to a new location X
that X
is not in that list (eg with nonmember(X,Visited)
). 然后,您必须确保在转到新位置X
X
不在该列表中(例如,具有nonmember(X,Visited)
)。
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