[英]summing up the values in last column using awk
I have a tab delimited file of five columns and it looks like this: 我有一个由五列组成的制表符分隔文件,它看起来像这样:
chr1 0 210515280 249250621 0.844593
chr1 1 15116879 249250621 0.0606493
chr1 2 9272046 249250621 0.0371997
chr1 3 5395181 249250621 0.0216456
chr1 4 3089690 249250621 0.0123959
chr1 5 1767270 249250621 0.00709033
chr1 6 1001501 249250621 0.00401805
chr1 7 590059 249250621 0.00236733
chr1 8 367487 249250621 0.00147437
chr1 9 247265 249250621 0.000992034
I want to add the values in last column and print it. 我想在最后一列中添加值并打印出来。
What I am doing: 我在做什么:
awk '{if($1="chr1") total += $5 } END { print total }'<file
and its not working. 它不起作用。
Any suggestions 有什么建议么
Thank you 谢谢
You need to use ==
for comparison and no need to do use <file
: 您需要使用==
进行比较,而无需使用<file
:
awk '$1 == "chr1" { total += $5 } END { print total }' file
$1="chr1"
is actually just assigning chr1
to $1
and it will always return true. $1="chr1"
实际上只是将chr1
分配给$1
,它将始终返回true。
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