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系统托盘图标无响应

[英]System tray icon is not responsive

When I open my application then the application is waiting for a connection to the server, I have done that by calling a slot run() which waits for a acknowledgement packet from server and when it receives it then it hides "Waiting for connection" string and loads other things. 当我打开我的应用程序然后应用程序正在等待连接到服务器时,我已经通过调用插槽run()等待来自服务器的确认数据包并且当它接收它然后它隐藏“等待连接”字符串并加载其他东西。 The problem is that when it waits for a packet then the system tray icon is not responding to anything, when the server sends packet and application loads then the system tray icon starts responding (for right-click menu). 问题是当它等待数据包时系统托盘图标没有响应任何东西,当服务器发送数据包和应用程序加载时,系统托盘图标开始响应(对于右键单击菜单)。

I am using ZeroMQ for IPC. 我正在使用ZeroMQ进行IPC。

I have something like this: 我有这样的事情:

int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
    MainWindow w;
    w.show(); 

    //THIS PART
    QTimer::singleShot(2000,&w,SLOT(run()));

    return a.exec();
}

You block the event loop. 您阻止事件循环。 This won't ever work. 这将永远不会奏效。 Unfortunately, ZMQ doesn't offer any platform-specific message loop integration. 不幸的是,ZMQ不提供任何特定于平台的消息循环集成。 Thus you have to use it in a separate thread. 因此,您必须在单独的线程中使用它。

This is much easier since it's bad design anyway to put networking code in a widget class. 这更容易,因为无论如何将网络代码放入窗口小部件类中都是糟糕的设计。

Create a ZMQ object that encapsulates your networking, and push it to a separate thread. 创建一个封装网络的ZMQ对象,并将其推送到单独的线程。 As long as all your communication with that ZMQ instance is over signals/slots or QMetaObject::invokeMethod , you'll be OK. 只要你与ZMQ实例的所有通信都是通过信号/槽或QMetaObject::invokeMethod ,你就可以了。

See this answer for code to Thread . 有关Thread代码,请参阅此答案

class ZMQ : public QObject {
  Q_OBJECT
  Q_SLOT void run() {
    ...
    forever {
      socket.send(request,0);
      socket.recv(&response);
      if(response.compare("login") == 0) {
        emit loggedIn();
        socket.close();
        return;
      }
    }
  }
public:
  ZMQ() {}
  Q_SIGNAL void loggedIn();
};

int main(int argc, char *argv[])
{
    QApplication a(argc, argv);
    ZMQ zmq;
    Thread thread; // see https://stackoverflow.com/a/25230470/1329652
    MainWindow w;

    w.connect(&zmq, SIGNAL(loggedIn()), SLOT(loggedIn()));
    zmq.moveToThread(&thread);
    thread.start();

    QMetaObject::invokeMethod(&zmq, "run");

    w.show(); 
    return a.exec();
}

You need to run the code currently in Mainwindow::run() in a separate thread for it to not block the event loop. 您需要在单独的线程中运行当前Mainwindow :: run()中的代码,以便不阻止事件循环。

Make a new QObject with a run slot containing the same code and move it to its own thread. 使用包含相同代码的运行槽创建一个新的QObject,并将其移动到自己的线程。 Something like this: 像这样的东西:

QThread *thread = new QThread;
thread->start();
qobject_with_run_slot->moveToThread(thread);
QTimer::singleShot(2000, qobject_with_run_slot, SLOT(run()));

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