如何使用C ++在没有readline的情况下显示字符串中的多个单词？

Question

I'm using Visual C++ 6.0 and currently created a program that will print the output stored in string.

The problem is when I entered words with space, only the first word is visible in the output.

Example:

Enter your address: new york
new
Press any key to continue

I want this:

Enter your address: new york
new york
Press any key to continue

Also, I tried to use getline but when I entered words, It will first print blank space then stored the last output before the current one.

Here's my code:

#include <iostream>
#include <string>

using namespace std;

void main()
{
  string address1;
  cout<<"Enter your address:";
  cin>> address1;
  // getline(cin, address1); code when using getline
  cout<<address1<<"\n";
}

Answer 1

Use std::getline (std::cin, address1); , not cin. Because cin takes space as delimiter.

Answer 2

What about this one? Kind of getline concept, presuming newline character is '\\n', change as required according to your platform, unix or windows etc

int main()
{
  string addrpart, address1;
  cout<<"Enter your address:";
  cin>> addrpart;
  while (addrpart != "x") {
    address1 += addrpart + " ";
    addrpart = "x";
    cin>> addrpart;
  }
  cout<<address1<<"\n";
}

Answer 3

Here you go

#include <iostream>
#include <string>

using namespace std;

int main( int argc, char** argv )
{
  string userinput;

  cout << "Enter your address:";
  getline ( cin, userinput );
  cout << userinput;

  return 0;
}

$ g++ a.cpp -o app
$ ./app
Enter your address:new york
new york

Answer 4

you are doing it correct, but the main problem is that you are using cin while you should avoid it and use getline(cin,address1) because cin will only take a single word and it will not take anyhting which you type after space. On the other hand getline(cin,address1) can take a complete sentence along with spaces

Read the comments and use this code

#include <iostream>
#include <string>

using namespace std;

int main()//using int main()
{

  string address1;

  cout<<"Enter your address:";

  //cin>> address1; Don't use it

  getline(cin, address1);//use this

  cout<<address1<<"\n";

  return 0;//returning an integer 0
}