用javascript中的正则表达式匹配其他两个字符串之间的字符串

Question

How can I use regex in javascript to match the phone number and only the phone number in the sample string below? The way I have it written below matches "PHONE=9878906756", I need it to only match "9878906756". I think this should be relatively simple, but I've tried putting negating like characters around "PHONE=" with no luck. I can get the phone number in its own group, but that doesn't help when assigning to the javascript var, which only cares what matches.

REGEX:

/PHONE=([^,]*)/g

DATA:

3={STATE=, SSN=, STREET2=, STREET1=, PHONE=9878906756 , MIDDLENAME=, FIRSTNAME=Dexter, POSTALCODE=, DATEOFBIRTH=19650802, GENDER=0, CITY=, LASTNAME=Morgan

Answer 1

The way you're doing it is right, you just have to get the value of the capture group rather than the value of the whole match:

var result = str.match(/PHONE=([^,]*)/); // Or result = /PHONE=([^,]*)/.exec(str);
if (result) {
    console.log(result[1]); // "9878906756"
}

In the array you get back from match , the first entry is the whole match, and then there are additional entries for each capture group.

You also don't need the g flag.

Answer 2

只需使用dataAfterRegex.substring(6)取出前6个字符（即PHONE=部分）。

Answer 3

Try

var str = "3={STATE=, SSN=, STREET2=, STREET1=, PHONE=9878906756, MIDDLENAME=, FIRSTNAME=Dexter, POSTALCODE=, DATEOFBIRTH=19650802, GENDER=0, CITY=, LASTNAME=Morgan";

var ph = str.match(/PHONE\=\d+/)[0].slice(-10);

console.log(ph);